I for sure thought I got eliminated in that second round! Opsies!

Resurrection Roll: Rolled: 1 (1) [1d100]

What are the odds?

Herm @ 22/3/2022 10:32

What are the odds?

If I had to guess, one in a hundred.

Got em

What’s the s3 spice Kat?

Last one sitting doesn’t count, that’s the opposite of spice

You roll for someone else and someone rolls for you.

two dice and add them together, roll a 100 and get a bonus dice for next round only (get two or 3 and add an additional round per 100 rolled)

Maybe just a simple roll twice and take the higher roll. Lowest is out

Whoever’s out rolled the lowest overall with two rolls, they’ve got no one to blame but themselves!

Roll a d5 for every person alive in the game. Would likely increase the odds of matching with someone else as the game progressed.

You'd probably have to set a fixed number for the first round, as sign-ups happen as the round progresses, but after that, it'd be easy.

Curtis @ 25/3/2022 6:43

Maybe just a simple roll twice and take the higher roll. Lowest is out Whoever’s out rolled the lowest overall with two rolls, they’ve got no one to blame but themselves!

This one sounds good. After "last one sitting" we can try this. I don't mind Vern's one lols bc I did wanna do one where each round is determined by the dice beforehand if it's lowest or highest.

What do you mean by rolling d5 for every person? @Spin. I feel slow

I wouldn't put an ounce of faith into Last One Sitting

Kat @ 26/3/2022 9:19

Curtis @ 25/3/2022 6:43 Maybe just a simple roll twice and take the higher roll. Lowest is out Whoever’s out rolled the lowest overall with two rolls, they’ve got no one to blame but themselves! This one sounds good. After "last one sitting" we can try this. I don't mind Vern's one lols bc I did wanna do one where each round is determined by the dice beforehand if it's lowest or highest. What do you mean by rolling d5 for every person? @Spin. I feel slow

If there are 10 people standing, then each person would roll a 10d5. And the sum would be your total. I think that works with the roll code. Test below.

Rolled: 33 (4+3+4+3+1+3+3+5+2+5) [10d5]

As the number of people is diminished, then the spread in numbers is reduced, making it more likely that multiple people roll the same total.

Could do one where when the round ends the host rolls a d2 to see if the lowest or highest roller gets eliminated.

Keeps more people on the edge.

The one or two people in the exact middle get eliminated. Middle person will shift with every new roll